Question

$\text{In the given figure,}\Delta ABC\text{and}\Delta OBC\text{are both isosceles.}$
$\text{It can be concluded that:}$

• A. $\Delta AOB\cong \Delta AOC$
  
• B. R.H.S. rule is applied
• C. S.S.S. rule is applied
• D. $\Delta AOB\text{is not congruent to}\Delta AOC$

Answer 1

Answer: (A), (C)

The correct options are
A $\Delta AOB\cong \Delta AOC$

C S.S.S. rule is applied


$\text{In}\Delta AOB\text{and}\Delta AOC,AB=AC\text{(Sides of isosceles}\Delta ABC\text{)}.OB=OC\text{(Sides of isosceles}\Delta OBC\text{)}.AOiscommon\therefore \Delta AOB\cong \Delta AOC\text{(by SSS congruence)}$