Given: ∠POR=120°.
Construction: Consider the arc PQR. Consider a point S not on this arc, but on the circumference of the circle. Join PS and RS.
Arc PQR subtends ∠POR at centre and ∠PSR on the remaining part of the circle (at the point S).
We know that, the angle subtended by an arc at the centre is double the angle subtended by it on any remaining points of the circle.
So, ∠PSR=12∠POR.
⟹∠PSR=12×120°=60°
Since PQRS is a cylic quadrilateral, we have its opposite angles to be supplementary.
⟹∠PQR+∠PSR=180°
⟹∠PQR+60°=180°
⟹∠PQR=180°−60°=120°