In the given figure, side BC of ΔABChas been produced on the left-hand side from B to D and on the right-hand side from C to E. If ∠ABD=106∘ and ∠ACE=118∘,find the measure of each anlge of the triangle.
Side BC of triangle ABC is produced to D.
∴∠ABD=∠A+∠C⇒106°=∠A+∠C ...(i)
Also, side BC of triangle ABC is produced to E.
∠ACE=∠A+∠B⇒118°=∠A+∠B ...(ii)
Adding (i) and (ii), we get:∠A+∠A+∠B+∠C=106+118°
⇒∠A+∠B+∠C+∠A=224° (∵∠A+∠B+∠C=180°)
⇒180°+∠A=224°⇒∠A=44°
∴∠B=118°-∠A (Using ii)
⇒∠B=118-44°⇒∠B=74°
And,
∠C=106°-∠A (Using i)
⇒∠C=106-44°⇒∠C=62°