Question

$\text{In the signal-space diagram of a 16-ary Quadrature Amplitude Modulation (QAM). message symbols are placed symmetrically about the origin. If}{E}_0\text{is the energy of the signal with the lowest amplitude and}{E}_{\text{avg}}\text{is the average transmitted symbol energy. then the value of the ratio}\frac{E_{\text{avg}}}{E_0}\text{will be}$

• A. 8
• B. 10
• C. 16
• D. 1

Answer 1

The correct option is B 10

For an M-ary QAM,
$E_{\text{avg}}=\frac{2(M-1)}{3}{E}_0$

For 16-ary QAM,
$E_{\text{avg}}=\frac{2(16-1)}{3}{E}_0=10E_0$
$\frac{E_{\text{avg}}}{E_0}=10$