Question

$\text{In}△ABC,\angle C={60}^{\circ }\text{and}\angle C>\angle B.\text{Which is the longest side of the triangle?}$

• A. AB
• B. BC
• C. AC
• D. Cannot be determined

Answer 1

The correct option is B BC

In $△$ABC, it is given that $\angle C={60}^{\circ }$ and $\angle C>\angle B$.
Let us suppose that $\angle$C is just greater than $\angle$B and that $\angle$B is equal to ${59}^{\circ }$.
Then, the measure of $\angle$A would be equal to "${180}^{\circ }$ – (${60}^{\circ }$ + ${59}^{\circ }$)", which is equal to ${61}^{\circ }$.
So, in any case $\angle$A would be greatest of all the angles in the triangle.
We know, in a triangle,side opposite to the larger (greater) angle is longer.
The side opposite to $\angle A$ is BC.
Hence, BC is the longest side of triangle ABC.