Question

$\text{John drinks 4 glasses of juice, each containing}\frac{1}{6}\text{L of juice. William on the other hand drinks}\text{2 glasses of juice, each containing}\frac{1}{3}\text{L of}\text{juice. Who drinks more juice?}$

• A. Cannot be determined.
• B. William
• C. Both drink the same amount of juice
• D. John

Answer 1

The correct option is C Both drink the same amount of juice

$Joh{n}^{\prime }scase:$

$\text{Number of glasses}=4$
$\text{Amount of juice in each glass}=\frac{1}{6}\text{L}$
$\text{Total amount of juice}=4\times \frac{1}{6}\text{L}$

$\text{Calculating}4\times \frac{1}{6}\text{L},\text{we get:}$


$\text{In 1 glass, the amount of juice}=1\times \frac{1}{6}\text{L}$
$\therefore \text{In 4 glasses, the amount of juice}=4\times \frac{1}{6}\text{L}=\frac{4}{6}\text{L}$

$\text{Now,}\frac{4}{6}=\frac{4÷2}{6÷2}=\frac{2}{3}$

$\therefore \text{John drinks}\frac{2}{3}\text{L of juice.}$

$Willia{m}^{\prime }scase:$

$\text{Number of glasses}=2$
$\text{Amount of juice in each glass}=\frac{1}{3}\text{L}$
$\text{Total amount of juice}=2\times \frac{1}{3}\text{L}$

$\text{Calculating}2\times \frac{1}{3}\text{L},\text{we get:}$


$\text{In 1 glass, the amount of juice}=1\times \frac{1}{3}\text{L}$
$\therefore \text{In 2 glasses, the amount of juice}=2\times \frac{1}{3}\text{L}=\frac{2}{3}\text{L}$

$\therefore \text{William drinks}\frac{2}{3}\text{L of juice}$

$\text{Hence, both John and William drink the}\text{same amount of juice.}$