Let A-x - R- x3-1and B-x - R- x2-1- then

A={x ∈ R: x^3=1} x^3 1=0 ⇒ (x 1)(x^2+x+1)=0 ⇒ x=1 [∵ x ∈ R] ∴ A={1} B={x ∈ R: x^2=1} nbsp; nbsp; B={ 1,1} nbsp; nbsp; ...

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Set Builder Form

Let A=x ∈ R: ...

Question

$Let A = {x \in R : x^{3} = 1}$
$and B = {x \in R : x^{2} = 1}, then$

A \subset B

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A = B

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B \subset A

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A

and

B

are disjoint.

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Solution

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Similar questions

Let A = {x \in R : x^{3} = 1}

and B = {x \in R : x^{2} = 1}, then

Which of the following sets are equal ?

(i) A = {1, 2, 3}

(ii) B = { $x ϵ R : x^{2} - 2 x + 1 = 0$ }

(iii) C = {1, 2, 2, 3}

(iv) D = { $x ϵ R : x^{3} - 6 x^{2} + 11 x - 6 = 0$ }.

A = \{1, 2, 3\};

B = \{x \in R : x^{2} - 2 x + 1 = 0\};

C = \{1, 2, 2, 3\};

D = \{x \in R : x^{3} - 6 x^{2} + 11 x - 6 = 0\}

A = {x \in R : x^{2} - 5 | x | + 6 = 0}

n (A) =

A = {\begin{matrix} x \in R : x^{2} + 6 x - 7 < 0 \end{matrix}}

B = {\begin{matrix} x \in R : x^{2} + 9 x + 14 < 0 \end{matrix}}

(A \cap B) = (- 2, 1)

(A ∖ B) = (- 7, - 2)

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