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Question

Let (x21)dxx33x4+2x21=f(x)+c and λ=limxf(x), then the absolute value of λ3 is (where c is the constant of integration)

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Solution

f(x)=(x21)dxx53+2x21x4f(x)=(1x31x5)dx3+2x21x4Put, 3+2x21x4=tdtdx=4x3+4x514dtt=12t+cf(x)=123+2x21x4 ,λ=limxf(x)=32|λ3|=12=0.50

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