Let a- - - - - k- c- - - k- and a vector b be such that a-b-c and a -b-3- Then -b- equals -

We have a× nbsp;b=c a×(a× nbsp;b)= nbsp; nbsp;a×c (a. nbsp;b)a (a .a )b= a×c 3a 3b= 2î + nbsp;ĵ + nbsp;k̂ 3î + 3ĵ + 3k̂ 3b= 2î + nbsp;ĵ + ...

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Work Done as Dot Product

Let a= î + ĵ ...

Question

$Let \to a =^i +^j +^k, \to c =^j -^k$ and a vector $\to b$ be such that $\to a \times \to b = \to c$ and $\to a . \to b = 3$ . Then $| \to b |$ equals :

\frac{11}{3}

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\frac{11}{\sqrt{3}}

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\sqrt{\frac{11}{3}}

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\frac{\sqrt{1} 1}{3}

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Solution

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Similar questions

Let \to a =^i +^j +^k, \to c =^j -^k

\to b

\to a \times \to b = \to c

\to a . \to b = 3

| \to b |

\to a =^i +^j +^k, \to c =^j -^k

\to b

\to a \times \to b = \to c

\to a \cdot \to b = 3

| \to b |

\to a =^i -^j, \to b =^i +^j +^k

\to c

\to a \times \to c + \to b = \to 0

\to a \cdot \to c = 4

| \to c |^{2}

\to a =^i +^j +^k

\to b =^j -^k .

\to c

\to a \times \to c = \to b

\to a \cdot \to c = 3,

\to a \cdot (\to b \times \to c)

\to a =^i +^j +^k, \to c =^j -^k

\to a . \to b = 3, \to a \times \to b = \to c

3 \to b =

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