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Graham's Law of Effusion

Lysine has pK...

Question

$Lysine has p K_{a_{1}} = 2.18, p K_{a_{2}} = 8.95, p K_{a_{3}} = 10.53$ .

In which structure lysine will be present at $p H = 9.7$ .

A

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B

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C

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D

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Solution

The correct option is A
Lysine

As we can see Zwitter ion is formed by the combination of structure B and D.
Also, $p H > 7, average of p K_{a} values > 7$
$p H < 7, average of p K_{a} values < 7$
Given $p H of lysine is = 9.7$
So, $p H$ of ;ysine = average of $p K_{a}$ values of B and D structure.
Therefore,
$p H$ of lysine = $\frac{p K_{a_{2}} + p K_{a_{3}}}{2}$
$p H = \frac{8.95 + 10.53}{2}$
$p H = 9.74$
Hence, the correct answer is (C).

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Similar questions

Q. The structure of a basic amino acid, lysine, is given. The

p K_{a_{1}}, p K_{a_{2}}

p K_{a_{3}}

(A)

2.18, 8.95

10.53

p H

at isoelectric points

(p I)

?

p K_{a_{1}}, p K_{a_{2}} a n d p K_{a_{3}}

H_{3} P O_{4}

are 2.2, 7.2 and 12.3 respectively. The

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solution will be:

⎛ ⎜ ⎜ ⎝ H O O C - C | H^{\oplus} N H_{3} - C H_{2} C O O H ⎞ ⎟ ⎟ ⎠

The structure of aspartic acid is given.The

p K_{a_{1}}, p K_{a_{2}}

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respectively are:

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C O O H

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Q. Which of the following relation is correct regarding

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H_{3} P O_{4}

K_{a_{2}}

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