${MnO}_{2} (s) + 4 HCl(aq) \to {MnCl}_{2} (aq) + {Cl}_{2} (g) + 2 H_{2} O(l)$

Identify the oxidising and reducing agents in the above reaction.

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Solution

1. ${MnO}_{2}$ loses oxygen, therefore it is reduced, and thus it acts as an oxidizing agent. (1 mark)
2. $HCl$ loses hydrogen. It itself is oxidized, thus it acts as a reducing agent. (1 mark)
Therefore, in the reaction ${MnO}_{2}$ is oxidizing agent and $HCl$ is reducing agent.

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Similar questions

Q. Chlorine is prepared in the laboratory by treating manganese dioxide

({M n O}_{2})

with aqueous hydrochloric acid according to the reaction:

4 H C l (a q) + {M n O}_{2} (s) \to 2 H_{2} O (I) + {M n C l}_{2} (a q) + {C l}_{2} (g)

How many grams of

H C l

react with 5.0 g of manganese dioxide ?

${MnO}_{2} (s) + 4 HCl(aq) \to {MnCl}_{2} (aq) + {Cl}_{2} (g) + 2 H_{2} O(l)$

Identify the oxidising and reducing agents in the above reaction. Give an example of a decomposition reaction. [3 MARKS]

In the following reaction:
$M n O_{2} (s) + 4 H C l (a q) \to M n C l_{2} (a q) + C l_{2} (g) + 2 H_{2} O (l)$
Identify the oxidising and reducing agents.

{MnO}_{2} (s) + 4 HCl(aq) \to {MnCl}_{2} (aq) + {Cl}_{2} (g) + 2 H_{2} O(l)

In the above reaction, which one of them is getting reduced?

{MnO}_{2} (s) + 4 HCl(aq) \to {MnCl}_{2} (aq) + {Cl}_{2} (g) + 2 H_{2} O(l)

In the above reaction, which one of them is getting reduced?

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MnO2(s)+4HCl(aq)→MnCl2(aq)+Cl2(g)+2H2O(l) Identify the oxidising and reducing agents in the above reaction.

1. MnO2 loses oxygen, therefore it is reduced, and thus it acts as an oxidizing agent. (1 mark) 2. HCl loses hydrogen. It itself is oxidized, thus it acts as a reducing agent. (1 mark) Therefore, in the reaction MnO2 is oxidizing agent and HCl is reducing agent.

${MnO}_{2} (s) + 4 HCl(aq) \to {MnCl}_{2} (aq) + {Cl}_{2} (g) + 2 H_{2} O(l)$

Identify the oxidising and reducing agents in the above reaction.

1. ${MnO}_{2}$ loses oxygen, therefore it is reduced, and thus it acts as an oxidizing agent. (1 mark)
2. $HCl$ loses hydrogen. It itself is oxidized, thus it acts as a reducing agent. (1 mark)
Therefore, in the reaction ${MnO}_{2}$ is oxidizing agent and $HCl$ is reducing agent.