$Multiply a b c with (a b + b c + a c)$
$and find its value for a = 1, b = 0 and c = 2.$

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Solution

The correct option is B 0
$a b c \times (a b + b c + a c) = a b c \times a b + a b c \times b c + a b c \times a c = a^{2} b^{2} c + a b^{2} c^{2} + a^{2} b c^{2}$

On substituting,
$a = 1, b = 0, c = 2$
we get,
$(1^{2} \times 0^{2} \times 1) + (1 \times 0^{2} \times 1^{2}) + (1^{2} \times 0 \times 1^{2}) = 0 + 0 + 0 = 0$

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Multiply abc with (ab+bc+ac) and find its value for a=1,b=0 and c=2.

The correct option is B 0abc×(ab+bc+ac)=abc×ab+abc×bc+abc×ac=a2b2c+ab2c2+a2bc2 On substituting, a=1,b=0,c=2 we get, (12×02×1)+(1×02×12)+(12×0×12)=0+0+0=0

$Multiply a b c with (a b + b c + a c)$
$and find its value for a = 1, b = 0 and c = 2.$