CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

N drops of mercury of equal radii and possessing equal charges combine to form a big spherical drop. If each individual drop has capacitance C ,then the capacitance of the bigger drop compared to each individual drop is

A
N times
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
N23 times
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
N13 times
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
D
N53 times
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is C N13 times
Let the radius of small drop be r and big drop be R.

Capacitance of isolated spherical conductor is given by C=4πϵ0rSo, Capacitance of small drop of mercury is Cs=4πϵ0rCapacitance of bigger drop is Cb=4πϵ0R
The combined volume of the N drops is equal to the volume of bigger drop.

N×43πr3=43πR3

R=N13r

Thus, the capacitance of bigger drop is
Cb=N13Ca

Hence, option (c) is the correct answer.

flag
Suggest Corrections
thumbs-up
10
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Visualising Electric Fields - Electric Field Lines
PHYSICS
Watch in App
Join BYJU'S Learning Program
CrossIcon