Question

$\text{Prove that the diagonals of a paral lelogram bisect each other.}$

Answer 1

$\text{Given :}||\text{gm ABCD in which diagonals AC and BD bisect each other.}\text{To Prove : OA = OC and OB = OD}\text{Proof :}\because AB||CD\text{(Given)}\therefore \angle 1=\angle 2\text{(alternate)}\angle s\angle 3=\angle 4=\text{(alternate)}\angle sandAB=CD\text{(opposite sides of}||gm)\therefore \Delta COD\cong \Delta AOB\text{(A.S.A. rule)}\therefore OA=OCandOB=OD\text{Hence the result.}$