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Question

Show that 527+752+275 is exactly divisible by 14.

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Solution

Property:

abc=100a+10b+c ...(i)bca=100b+10c+a ...(ii)and cab=100c+10a+b ...(iii)Adding, (i), (ii) and (iii), we getabc+bca+cab=111a+111b+111c=111(a+b+c)=3×37(a+b+c)Now, let us try this method on527+752+275 to chck is it exactly divisible by 14Here, a=5, b=2, c=7527+752+275=3×37(5+2+7)=3×37×14Hence, it shos that 527+752+275 is exactly divisible by 14


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