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B
5(p−2)
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C
5(p+1)
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D
5(p−1)
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Solution
The correct option is D5(p−1) Given, the expression is 5p2−25p+20(p−4). Now, the numerator can be factorized as, 5p2−25p+20=5(p2−5p+4)=5[p2−p−4p+4]=5[p(p−1)−4(p−1)]=5(p−1)(p−4)Hence,5p2−25p+20(p−4)=5(p−1)(p−4)(p−4)=5(p−1)