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Question

Simplify the expression: 52wxyz(xy+yz+xz+y2)(z+x)104xy(xyz+xz2+yz2+y2z)

A
w(z+x)2
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B
w(zx)2
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C
x(zx)2
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D
x(z+x)2
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Solution

The correct option is A w(z+x)2
Given expression: 52wxyz(xy+yz+xz+y2)(z+x)104xy(xyz+xz2+yz2+y2z)

Taking 'z' common from the denominator, we get 52wxyz(xy+yz+xz+y2)(z+x)104xyz(xy+xz+yz+y2)

On cancelling out the common termsfrom the above expression, we get w(z+x)2.

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