The correct option is A w(z+x)2
Given expression: 52wxyz(xy+yz+xz+y2)(z+x)104xy(xyz+xz2+yz2+y2z)
Taking 'z' common from the denominator, we get 52wxyz(xy+yz+xz+y2)(z+x)104xyz(xy+xz+yz+y2)
On cancelling out the common termsfrom the above expression, we get w(z+x)2.