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Question

Find the value of 'n' such that
23(4n−1)−(2n−1+n3)=13n+43.

A
-54
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B
54
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C
-52
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D
52
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Solution

The correct option is D 52
Given expression: 23(4n1)(2n1+n3)=13n+43

By taking the LCM,
23(4n1)13(6n1n)=13n+43
The denominator of all the terms are same.
So, by removing the denominator,
2(4n1)(5n1)=n+4
8n25n+1=n+4
(8n5n)+(2+1)=n+4
3n1=n+4
3nn=4+1
2n=5
n=52

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