The correct option is D 52
Given expression: 23(4n−1)−(2n−1+n3)=13n+43
By taking the LCM,
23(4n−1)−13(6n−1−n)=13n+43
The denominator of all the terms are same.
So, by removing the denominator,
2(4n−1)−(5n−1)=n+4
8n−2−5n+1=n+4
(8n−5n)+(−2+1)=n+4
3n−1=n+4
3n−n=4+1
2n=5
n=52