Solve for x-6x-7-2x-1-3x-1-x-5

Given equation: 6x 7/2x+1=3x+1/x+5 ⇒ (6x 7)(x + 5) = (3x + 1)(2x + 1) ⇒ 6x^2 + 30x – 7x – 35 = 6x^2 + 3x + 2x + 1 ⇒ 23x – 3x – 2x = 35 + 1 ⇒ 18x = 36 ⇒ ...

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Byju's Answer

Standard VII

Mathematics

Solving an Equation

Solve for x:6...

Question

$Solve for x : \frac{6 x - 7}{2 x + 1} = \frac{3 x + 1}{x + 5}$
2

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Solution

The correct option is A 2
Given equation:

$\frac{6 x - 7}{2 x + 1} = \frac{3 x + 1}{x + 5}$

$\Rightarrow (6 x - 7) (x + 5) = (3 x + 1) (2 x + 1)$

$\Rightarrow 6 x^{2} + 30 x - 7 x - 35 = 6 x^{2} + 3 x + 2 x + 1$

$\Rightarrow 23 x - 3 x - 2 x = 35 + 1$

$\Rightarrow 18 x = 36$

$\Rightarrow x = \frac{36}{18}$

$\Rightarrow x = 2$

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Similar questions

Q. Evaluate:

\frac{3 x + 1}{6 x + 7} - \frac{x + 1}{2 x + 3} = 0

Solve :

$(i) \frac{1}{3} x - 6 = \frac{5}{2} (i i) \frac{2 x}{3} - \frac{3 x}{8} = \frac{7}{12} (i i i) (x + 2) (x + 3) + (x - 3) (x - 2) - 2 x (x + 1) = 0 (i v) \frac{1}{10} - \frac{7}{x} = 35 (v) 13 (x - 4) - 3 (x - 9) - 4 (x + 4) = 0 (v i) x + 7 - \frac{8 x}{3} = \frac{17 x}{6} - \frac{5 x}{8} (v i i) \frac{3 x - 2}{4} - \frac{2 x + 3}{3} = \frac{2}{3} - x (v i i i) \frac{x + 2}{6} - (\frac{11 - x}{3} - \frac{1}{4}) = \frac{3 x - 4}{12} (i x) \frac{2}{5 x} - \frac{5}{3 x} = \frac{1}{15} (x) \frac{x + 2}{3} - \frac{x + 1}{5} = \frac{x - 3}{4} - 1 (x i) \frac{3 x - 2}{3} + \frac{2 x + 3}{2} = x + \frac{7}{6} (x i i) x - \frac{x - 1}{2} = 1 - \frac{x - 2}{3} (x i i i) \frac{9 x + 7}{2} - (x - \frac{x - 2}{7}) = 36 (x i v) \frac{6 x + 1}{2} + 1 = \frac{7 x - 3}{3}$

Q. Solve

\frac{6 x - 7}{6 x - 2} = \frac{3 x - 1}{3 x + 5}

Q. Solve for

x : (3 x + 4) (2 x - 5) - 122 = (6 x - 1) (x + 10)

Q. Simplify:

2 x^{2} + 5 x - 1 + 8 x + x^{2} + 7 - 6 x + 3 - 3 x^{2}

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Solve for x:6x−72x+1=3x+1x+52

The correct option is A 2Given equation: 6x−72x+1=3x+1x+5 ⇒(6x−7)(x+5)=(3x+1)(2x+1) ⇒6x2+30x–7x–35=6x2+3x+2x+1 ⇒23x–3x–2x=35+1 ⇒18x=36 ⇒x=3618 ⇒x=2

$Solve for x : \frac{6 x - 7}{2 x + 1} = \frac{3 x + 1}{x + 5}$
2