Solve for x- 8x-1-3x-2-23-25-25-42-3

The correct option is A 3/2(8x+1)/3x+2=2 Transposing 3x+2 to the RHS, we get, 8x+1=2(3x+2) ⇒ 8x+1=6x+4 Transposing 6x to LHS and 1 to RHS, we have 8x 6x=4 ...

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Byju's Answer

Standard VIII

Mathematics

Solving by Transposing

Solve for x: ...

Question

$Solve for x:$

$\frac{8 x + 1}{3 x + 2} = 2$

\frac{3}{2}

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\frac{5}{2}

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\frac{5}{4}

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\frac{2}{3}

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Solution

The correct option is A $\frac{3}{2}$
$\frac{(8 x + 1)}{3 x + 2} = 2 Transposing 3x+2 to the RHS, we get, 8 x + 1 = 2 (3 x + 2) \Rightarrow 8 x + 1 = 6 x + 4 Transposing 6x to LHS and 1 to RHS, we have 8 x - 6 x = 4 - 1 \Rightarrow 2 x = 3 Transposing 2 to the LHS, we get x = \frac{3}{2}$

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Similar questions

Solve for x:

\frac{8 x + 1}{3 x + 2} = 2

Q. The value of

{(\frac{23}{25})}^{0} \times {(\frac{- 1}{2})}^{5} \times 2^{3} \times {(\frac{3}{4})}^{2}

is _______.

Q. Simpify and express following as a rational number :

{(\frac{3}{4})}^{2} \times {(\frac{- 1}{2})}^{5} \times 2^{3}

Q. Amelia was feeding the data points of a data set as follows:

$46$	$25$	$23$	$24$	$6$
$4$	$3$	$21$	$25$	$42$
$25$	$12$	$24$	$23$	$23$

She mistakenly entered the number

42

. Given that the data set is trimodal data, the correct value in place of

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is .

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\frac{4^{3} \times 6^{6} \times 2^{5}}{2^{3} \times 4^{2} \times 3^{2}}

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Solve for x: 8x+13x+2=2

The correct option is A 32(8x+1)3x+2=2Transposing 3x+2 to the RHS, we get, 8x+1=2(3x+2)⇒8x+1=6x+4Transposing 6x to LHS and 1 to RHS, we have 8x−6x=4−1⇒2x=3Transposing 2 to the LHS, we get x=32

$Solve for x:$

$\frac{8 x + 1}{3 x + 2} = 2$

The correct option is A $\frac{3}{2}$
$\frac{(8 x + 1)}{3 x + 2} = 2 Transposing 3x+2 to the RHS, we get, 8 x + 1 = 2 (3 x + 2) \Rightarrow 8 x + 1 = 6 x + 4 Transposing 6x to LHS and 1 to RHS, we have 8 x - 6 x = 4 - 1 \Rightarrow 2 x = 3 Transposing 2 to the LHS, we get x = \frac{3}{2}$