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Question

Solve for x in the equation log[log(2+log2(x+1))]=0


A

281

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B

28

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C

221

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D

381

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Solution

The correct option is A

281


Rewrite the equation as
log[log(2+log2(x+1))]=log(1),
[since log(1) = 0]

log(2+log2(x+1))=1

2+log2(x+1)=10

log2(x+1)=8

x+1=28

x=281


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