Solve for x in the equation log[log(2+log2(x+1))]=0
28−1
28
22−1
38−1
Rewrite the equation as log[log(2+log2(x+1))]=log(1), [since log(1) = 0]
log(2+log2(x+1))=1
2+log2(x+1)=10
log2(x+1)=8
x+1=28
x=28−1