The correct option is B Both A and R are true but R is not correct explanation of A.
Magnetic force on the current carrying conductor, →FB=(i→l×→B) ⇒FB=ilBsin0∘=0 [∵→l||→B]
∴ Statement A is correct.
Due to the presence of equal number of electrons and protons inside a conductor, the net charge on the current wire would be zero.
So, statement R is also correct but reason behind statement A is →FB=(i→l×→B) & θ=0∘
Hence, option (b) is the correct alternative.