$Statement :$ Alumina $(A l_{2} O_{3})$ and silica $(S i O_{2})$ get dissolved in a concentrated solution of NaOH under pressure. $A l (O H)_{3}$ is precipitated when $C O_{2}$ is passed or by seeding with some freshly precipitated $A l (O H)_{3}$ .

If the statement is true enter 1 else 0.

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Solution

With hot concentrated NaOH solution the Alumina dissolves as sodium tetrahydroxyaluminate ( $N a A l (O H)_{4}$ )

$A l_{2} O_{3} + 2 N a O H + 3 H_{2} O \to N a A l (O H)_{4}$
Silica reacts with hot and concentrated NaOH forming sodium silicate ( $N a_{2} S i O_{3}$ )

$N a O H + S i O_{2} \to N a_{2} S i O_{3} + H_{2} O$

$A l (O H)_{3}$ is precipitated by passing $C O_{2}$ and seeded with freshly precipitated $A l (O H)_{3}$ which induces precipitation of $A l (O H)_{3}$ as follows.

$2 N a A l (O H)_{4} + C O_{2} \to 2 A l (O H)_{3} p p t . ↓ + N a_{2} C O_{3} + H_{2} O$

The given statement is true.
The correct entry is 1.

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