106

You visited us 106 times! Enjoying our articles? Unlock Full Access!

Adding Two Decimal Numbers

Sum of 1.324 ...

Question

$Sum of 1.324 and 11.67 is$

Open in App

Solution

Let's add 1.324 and 11.67:

Step 1: Add one zero to the right of the decimal number 11.67 to have 3 digits after a decimal point i.e. 11.670 because 1.324 has 3 digits after a decimal point.

Step 2: Align the decimal numbers according to their place values one below the other i.e. allign the thousandths digits 4 and 0, allign the hundredths digits 2 and 7, allign the tenths digits 3 and 6 and allign the ones digits 1 and 1.
$T O . t h t h$
$1.3 24 + 1 1.6 70$
-------------

Step 3: Add each column of digits, starting on the right.

Finally, put the decimal point of the sum vertically below the other decimal points.

$∴ Sum of 1.324 and 11.67 is 12.994 .$

Suggest Corrections

Similar questions

x_{1} = \frac{1}{1 \cdot 3} + \frac{1}{3 \cdot 5} + \frac{1}{5 \cdot 7} + \dots

10

y_{1} = Sum of roots of equation of x^{2} - 7 x + 10 = 0

(x_{1}, y_{1})

\frac{(21 x)^{2}}{100} - \frac{y^{2}}{(7 b)^{2}} = - 1

b

S : {(x + 2)}^{2} + {(y - 8)}^{2} = 16

P : y^{2} = 8 x . T A

T B

T

P = 0

S = 0

T A + T B

A

B

\begin{matrix} List I & List II (A) & If T \equiv (a, b), then (a + b) equals & (P) & 6 (B) & Sum of ordinates of A and B is & (Q) & 8 (C) & Minimum value of (T A + T B) is & (R) & 10 (D) & Area of Δ T A B is & (S) & 12 \end{matrix}

25^{\circ} C

C r^{3 +} + e^{-} \to C r^{2 +}, g i v e n E^{0} = - 0.424 V C r^{2 +} + 2 e^{-} \to C r (s), g i v e n E_{0} = - 0.9 V F i n d E^{0} a t 25^{\circ} C f o r C r^{3 +} (a q) + 3 e^{-} \to C r (s)

25^{\circ} C

C r^{3 +} + e^{-} \to C r^{2 +}, g i v e n E^{0} = - 0.424 V C r^{2 +} + 2 e^{-} \to C r (s), g i v e n E_{0} = - 0.9 V F i n d E^{0} a t 25^{\circ} C f o r C r^{3 +} (a q) + 3 e^{-} \to C r (s)

Join BYJU'S Learning Program