Question

$\text{The base of a right triangle is 48 cm and its hypotenuse is 50 cm long.The area of the triangle is}\left(a\right)168c{m}^2\left(b\right)252c{m}^2\left(c\right)336c{m}^2\left(d\right)504c{m}^2$

Answer 1

Case of right angled triangle :-

base = 48cm
hypotenuse= 50cm .

By Pythagoras theorem , we get

$h^2=b^2+p^2$
So ,

$p^2=h^2-b^2$

$p^2={50}^2-{48}^2$

= 2500 - 2304 = 196


= p = $\sqrt{196}$


= p = 14
So ,

Perpendicular = 14 cm .

Now area of triangle = 1 / 2 x b x p
= 1 / 2 x 48 x 14
= 48 x 7
= 336 $c{m}^2$