Question

$\text{The electron concentration in the n-type silicon bar is}1.5\times {10}^{15}/c{m}^3\text{. Then Hall co-efficient}\left(R_H\right)\text{of the above silicon bar is\_\_\_\_\_\_\_\_}\times {10}^{3}c{m}^3/C\text{(Assume charge of electron is}1.6\times {10}^{-19}C).$

Answer 1

$\text{Given,}\text{Electron concentration in the n-type silicon bar is}n=1.5\times {10}^{15}/c{m}^2\text{Hall co-efficient,}{R}_H=\frac{1}{nq}\left(or\right)\frac{1}{ne}\therefore R_H=\frac{1}{1.5\times {10}^{15}\times 1.6\times {10}^{-19}}=4.16\times {10}^{3}c{m}^3/C$