The ends of latus rectum of parabola x2+8y=0 are
(−4,−2) and (4,−2)
Given,
x2+8y=0
⇒x2=−8y
On comparing with x2=−4ay, we get
⇒a=2
So , focus of x2=−4ay is (0,−a)Hence focus=(0,−2)
The end points of latus rectum of the parabola
x2=−4ay are (−2a,−a),(2a,−a).
Ends of latus rectum =(4,−2),(−4,−2) .
Hence, the correct answer is Option c.
Trick: Since the ends of latus rectum lie on parabola so only points
(−4,−2) and (4,−2) satsify the parabola.