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Question

The LCM of (x−1)3(x+8) and (x−1)(x+8)2 is:

A
(x1)3(x+8)2
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B
(x1)3(x+8)3
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C
(x1)2(x+8)2
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D
(x1)2(x+8)3
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Solution

The correct option is A (x1)3(x+8)2
The common irreducible factors occuring in (x1)3(x+8) and (x1)(x+8)2 are (x1) and (x+8)
The greatest exponents of these factors respectively are 3 and 2.
Hence, the LCM = (x1)3× (x+8)2 = (x1)3(x+8)2.

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