The number of planks of dimensions4-m- 5-m -2 mthat can be stored in a pit which is 40 m long- 12 m wide and 16 m deep-is- a-190-b-192-c-184-d-180

The volume of pit = 40 m × 12 m × 16 m = 7680m^3 Volume of planks = 4 m× 5 m × 2 = 40m^3 Hence, number of planls = 7680/40 = 192 192 planks can be stored in ...

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Standard IX

Mathematics

Volume of a cuboid

The number of...

Question

$The number of planks of dimensions (4 m \times 5 m \times 2 m) that can be stored in a pit which is 40 m long, 12 m wide and 16 m deep,is (a) 190 (b) 192 (c) 184 (d) 180$

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Solution

The volume of pit = $40 m \times 12 m \times 16 m = 7680 m^{3}$

Volume of planks = $4 m \times 5 m \times 2 = 40 m^{3}$

Hence, number of planls = $\frac{7680}{40}$ = 192

192 planks can be stored in a pit.

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The number of planks of dimensions(4 m×5 m×2m)that can be stored in a pit which is 40 m long, 12 m wide and 16 m deep,is(a) 190 (b) 192 (c) 184 (d) 180

The volume of pit = 40 m × 12 m× 16m=7680m3 Volume of planks = 4 m×5 m× 2 = 40m3 Hence, number of planls = 768040 = 192 192 planks can be stored in a pit.

$The number of planks of dimensions (4 m \times 5 m \times 2 m) that can be stored in a pit which is 40 m long, 12 m wide and 16 m deep,is (a) 190 (b) 192 (c) 184 (d) 180$

The volume of pit = $40 m \times 12 m \times 16 m = 7680 m^{3}$

Volume of planks = $4 m \times 5 m \times 2 = 40 m^{3}$

Hence, number of planls = $\frac{7680}{40}$ = 192

192 planks can be stored in a pit.