$The perimeter of a rectangle is 40 m and one of its side measures 8 m . Find the length of the other side.$

$10 m$

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$12 m$

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$11 m$

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$32 m$

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Solution

The correct option is B
$12 m$

$Perimeter of a rectangle = 40 m$

$\Rightarrow 2 (l + b) = 40$

$Where l and b are its length and breadth respectively.$

Given: One side of the rectangle measures 8 m.

$Let b = 8 m$

$\Rightarrow 2 (l + 8) = 40$

$\Rightarrow l + 8 = \frac{40}{2} = 20$

$\Rightarrow l = 20 - 8$

$\Rightarrow l = 12 m$

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