The value of (1+i)(1+i2)(1+i3)(1+i4) is
2
0
1
i
(1+i)(1+i2)(1+i3)(1+i4)=(1+i)(1−1)(1−i)(1+1) (∵ i2=−1, i3=−i and i4=1)=(1+i)(0)(1−i)(2)=0
The value of (1+i)4+(1−i)4 is
The value of (−i)13 is