CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

The value of a for which (a21)x2(a1)x+a24a+3=0 is an identity in x

A
1.0
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
B
1
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
C
01
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
Open in App
Solution

Given (a21)x2(a1)x+a24a+3=0
For this to be an identity in x, the coefficients of various powers of x and constant term must be zero.

Put coefficient of x2=0,
(a21)=0
(a+1)(a1)=0
a=1,1

Put coefficient of x=0,
(a1)=0
a=1

Put constant term =0,
a24a+3=0
(a1)(a3)=0
a=1,3

Hence, the common value of a is 1.
a=1

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Introduction to Quadratic Equations and Polynomials
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon