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Question

The value of ∣ ∣abbcbccdcdde∣ ∣,
where a,b,c,d,e are in A.P with common difference D.

A
D4
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B
D4
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C
2D4
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D
2D4
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Solution

The correct option is D 2D4
ba=cb=dc=ed=Dca=db=ec=2DR3R3R2Δ=∣ ∣abbcbccdDD2dD∣ ∣R2R2R1Δ=∣ ∣abbcDD2cDDD2dD∣ ∣C1C1C2Δ=∣ ∣Dbbc0D2cD0D2dD∣ ∣=D(2dD22cD2)=D.2D2(dc)=2D4

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