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Question

The value oflimx01cos3xxsin xcosx


A

2/5

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B

3/5

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C

3/2

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D

3/4

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Solution

The correct option is C

3/2


limx01cos3xxsin xcosx=limx0(1cos x)(1+cos x+cos2x)xsin xcos x=limx02sin2(x2)2sin(x2)cos(x2).x×(1+cosx+cos2x)cos x=limx0sin(x2)2(x2)×1+cosx+cos2xcos(x2)cos x=12×3=32


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