The value of lim x - 01-xsin -12 x-1-x2 is

The correct option is A 2 sin^ 12x/(1+x^2)=2tan^ 1x,the given limit=lim_x→ 02 tan^ 1x/x=2lim_x→ 0tan^ 1x/x=2(1)=2 Hence (a) is the correct answer. ...

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Standard XI

Mathematics

Sin2a and Cos2a in Terms of Tana

The value of ...

Question

$The value of l i m x \to 0 \frac{1}{x} s i n^{- 1} (\frac{2 x}{1 + x^{2}}) is$

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Solution

The correct option is A
2

$s i n^{- 1} \frac{2 x}{(1 + x^{2})} = 2 t a n^{- 1} x, the given limit = {lim}_{x \to 0} \frac{2 t a n^{- 1} x}{x} = 2 {lim}_{x \to 0} \frac{t a n^{- 1} x}{x} = 2 (1) = 2$
Hence (a) is the correct answer.

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The value of limx→ 01x sin−1(2x1+x2)is

The correct option is A 2 sin−12x(1+x2)=2tan−1x,the given limit=limx→02tan−1xx=2limx→0tan−1xx=2(1)=2 Hence (a) is the correct answer.

$The value of l i m x \to 0 \frac{1}{x} s i n^{- 1} (\frac{2 x}{1 + x^{2}}) is$

The correct option is A
2

$s i n^{- 1} \frac{2 x}{(1 + x^{2})} = 2 t a n^{- 1} x, the given limit = {lim}_{x \to 0} \frac{2 t a n^{- 1} x}{x} = 2 {lim}_{x \to 0} \frac{t a n^{- 1} x}{x} = 2 (1) = 2$
Hence (a) is the correct answer.