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Question

The values of constants a and b so thatlimx(x2+1x+1axb)=12,are


A

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B

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C

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D

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Solution

The correct option is A


limx(x2+1x+1axb)=12limx(x2+1)(ax+b)(x+1)x+1=12limxx2(1a)(a+b)xb+1x+1=121a=0 and a+b=12a=1 b=32


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