Use distributivity to solve 25 - 101-

To solve: 25 × 101 We know that by distributivity, a× (b+c) = a × b + a × c So, 25 × 101 = 25 × (100 + 1) = (25 × 100) + (25 × 1) = 2500 + 25 = 2525 nbs ...

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Byju's Answer

Standard VI

Mathematics

Distributive Property

Use distribut...

Question

$Use distributivity to solve 25 \times 101.$
2525

Open in App

Solution

The correct option is A 2525
$To solve: 25 \times 101$

$We know that by distributivity, a \times (b + c) = a \times b + a \times c$

$So, 25 \times 101$
$= 25 \times (100 + 1)$
$= (25 \times 100) + (25 \times 1) = 2500 + 25 = 2525$

Suggest Corrections

Similar questions

(1 + cos \frac{π}{10}) (1 + cos \frac{3 π}{10}) (1 + cos \frac{7 π}{10}) (1 + cos \frac{9 π}{10}) =

(1 + cos \frac{π}{10}) (1 + cos \frac{3 π}{10}) (1 + cos \frac{7 π}{10}) (1 + cos \frac{9 π}{10}) = \frac{1}{16}

Q. The value of expression

(1 - cos \frac{π}{10}) (1 + cos \frac{3 π}{10}) (1 + cos \frac{7 π}{10}) (1 - cos \frac{9 π}{10})

Q. The value of the expression

(1 + cos \frac{π}{10}) (1 + cos \frac{3 π}{10}) (1 + cos \frac{7 π}{10}) (1 + cos \frac{9 π}{10})

is?

Q. The value of the expression

(1 + c o s \frac{π}{10}) (1 + c o s \frac{3 π}{10}) (1 + c o s \frac{7 π}{10}) (1 + c o s \frac{9 π}{10})

Join BYJU'S Learning Program

Use distributivity to solve 25×101.2525

The correct option is A 2525To solve: 25×101 We know that by distributivity, a×(b+c)=a×b+a×c So, 25×101 =25×(100+1) =(25×100)+(25×1)=2500+25=2525

$Use distributivity to solve 25 \times 101.$
2525

The correct option is A 2525
$To solve: 25 \times 101$

$We know that by distributivity, a \times (b + c) = a \times b + a \times c$

$So, 25 \times 101$
$= 25 \times (100 + 1)$
$= (25 \times 100) + (25 \times 1) = 2500 + 25 = 2525$