Question

$\text{Using a scale of}1in:50ft\text{between the}$
$\text{actual and scale drawing of a mountain,}$
$\text{calculate the length A'B' in the scale drawing}$
$\text{of the mountain A'B'C'.}$

• A. 21 in
• B. 22 in
• C. 23 in
• D. 24 in

Answer 1

The correct option is D 24 in

$\text{The scale is}1in:50ft$

Since during scaling, sides of both the triangles ABC and A'B'C' are proportional to each other, we can write:

$\text{A'B' : AB}=1in:50ft$

$\therefore \text{A'B' =}\frac{1200\times 1}{50}=24in$