$What is the sum of first 11 odd numbers?$

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107

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121

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115

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Solution

The correct option is C 121
$The sum of n successive odd natural numbers starting from 1 is always equal to n^{2} .$

$\Rightarrow 1 + 3 + . . . + n = n^{2}$

$Hence, the sum of 11 successive odd nautral numbers is \Rightarrow 1 + 3 + 5 + 7 + 9 + 11 + 13 + 15 + 17 + 19 + 21 = 11 \times 11 = 121$

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