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Question

Which of the following are the factors of 12ab+9a+12+16b?


A

(3a4)and (4b3)

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B

(3a4)and (4b+3)

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C
(3a+4)and (4b+3)
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D
(3a+4)(4b3)
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Solution

The correct option is C (3a+4)and (4b+3)

Given, the expression is 12ab+9a+12+16b.

Taking 3a common from the firsttwo terms and 4 common from the last two terms, we get 12ab+9a+12+16b=3a(4b+3)+4(3+4b)=(3a+4)(3+4b)


So, (4b+3)and (3a+4)are the irreducible factors of the given expression.


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