$Which of the following is true for the commutativity of addition and multiplication of the numbers 7 and \frac{13}{2} ?$

7 + \frac{13}{2} = \frac{13}{2} + 7

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7 + (\frac{13}{2} + 8) = (7 + \frac{13}{2}) + 8

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7 \times \frac{13}{2} = \frac{13}{2} \times 7

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7 - \frac{13}{2} = \frac{13}{2} - 7

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Solution

The correct option is C $7 \times \frac{13}{2} = \frac{13}{2} \times 7$
$Given numbers: 7 and \frac{13}{2} Let a = 7 and b = \frac{13}{2}$

$Commutativity of addition states that, a + b = b + a \Rightarrow 7 + \frac{13}{2} = \frac{13}{2} + 7$

$Commutativity of multiplication states that a \times b = b \times a \Rightarrow 7 \times \frac{13}{2} = \frac{13}{2} \times 7$

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Similar questions

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Question 6
Using the given pattern, find the missing numbers:
$1^{2} + 2^{2} + 2^{2} = 3^{2}$
$2^{2} + 3^{2} + 6^{2} = 7^{2}$
$3^{2} + 4^{2} + 12^{2} = 13^{2}$
$4^{2} + 5^{2} + {- --- -}^{2} = 21^{2}$
$5^{2} + {- --- -}^{2} + 30^{2} = 31^{2}$
$6^{2} + 7^{2} + - --- - 2 = - --- - 2$