Question

$\text{Which rational number should be added to}\frac{-5}{9}\text{to get}\frac{-2}{3}?$

Answer 1

$\text{Required rational number}=\frac{-2}{3}-\left(\frac{-5}{9}\right)=\frac{-2}{3}+\frac{5}{9}$

$\therefore \text{LCM of 3 and 9=9}=\frac{-2\times 3}{3\times 3}+\frac{5\times 1}{9\times 1}(\because \text{LCM of 3 and 9=9})=\frac{-6+5}{9}=\frac{-1}{9}$