$Write the number of points of intersection of the curves 2y=-1 and y=cosec x.$

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Solution

$We want to find to find the value of x such t h a t c o s e c = \frac{- 1}{2} This not possible for any value of x.$

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2 y = 1

y = \cos x, 0 \leq x \leq 2 π

y = x^{2} - 5 x + 1

y = e^{- x}

Write the number of poits of intersection of the curves $2 y = 1 a n d y = c o s x, 0 \leq x \leq 2 π .$

y = \frac{1}{2}

y = s i n x i n t h e i n t e r v a l x \in [0, 4 π]

2 y = 1

y = sin x, - 2 π \leq x \leq 2 π

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