Write the number of values of θ in [θ,2π]that satisfy the equation sin2 θ−cos θ=14.
We have,sin2θ−cos θ=14⇒1−cos2θ−cos θ=14⇒cos2θ+cos θ−34=0⇒4cos2θ+4 cos θ−3=0⇒4cos2θ+6 cos θ−2 cos θ−3=0⇒2 cos θ[2 cos θ+3]−[2 cos θ+3]=0⇒(2 cos θ−1)(2 cos θ+3)=0∴ cos θ =12 or cos θ=−32∴Only for 2 values in [0,2π],cos θ =12,or the given equation is satisfied.