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Question

Write the number of values of θ in [θ,2π]that satisfy the equation sin2 θcos θ=14.

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Solution

We have,sin2θcos θ=141cos2θcos θ=14cos2θ+cos θ34=04cos2θ+4 cos θ3=04cos2θ+6 cos θ2 cos θ3=02 cos θ[2 cos θ+3][2 cos θ+3]=0(2 cos θ1)(2 cos θ+3)=0 cos θ =12 or cos θ=32Only for 2 values in [0,2π],cos θ =12,or the given equation is satisfied.


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