Zeroes of nbsp- nbsp-x-2-56x-108 nbsp- are-both positive-both negative-both equal-one negative and one positive-

The correct option is A both positive In a quadratic equation ax^2 + bx + c,both zeroes are positive nbsp;when a is positive, b nbsp;is negative nbsp;and ...

You visited us 4 times! Enjoying our articles? Unlock Full Access!

Byju's Answer

Standard IX

Mathematics

Zeros of a polynomial

Zeroes of n...

Question

$Zeroes of x^{2} - 56 x + 108 are$ ______.

both positive

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

both negative

No worries! We‘ve got your back. Try BYJU‘S free classes today!

one negative and one positive

No worries! We‘ve got your back. Try BYJU‘S free classes today!

both equal

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is A
both positive

In a quadratic equation $a x^{2} + b x + c$ ,both zeroes are positive when a is positive, b is negative and c is positive.

In this case, $x^{2} - 56 x + 108$ can be factorized as $(x - 2) (x - 54)$ .

$⟹$ the roots are 2 and 54; both are positive.

Suggest Corrections

Similar questions

Question 71

Using number line, how do you compare

(a) two negative integers?

(b) two positive integers?

The zeros of the quadratic polynomial $x^{2} + 88 x + 125$ are

(a) both positive (b) both negative

Write a pair of positive integers, a pair of negative integers, one positive and one negative integer whose

sum is $8$

Write a pair of positive integers, a pair of negative integers, one positive and one negative integer whose sum is $- 5$

Q. Addition of one negative and one positive integer is

Join BYJU'S Learning Program

Zeroes of x2−56x+108 are______.

The correct option is A both positive In a quadratic equation ax2+bx+c,both zeroes are positive when a is positive, b is negative and c is positive. In this case, x2−56x+108 can be factorized as (x−2)(x−54). ⟹the roots are 2 and 54; both are positive.

$Zeroes of x^{2} - 56 x + 108 are$ ______.

The correct option is A
both positive

In a quadratic equation $a x^{2} + b x + c$ ,both zeroes are positive when a is positive, b is negative and c is positive.

In this case, $x^{2} - 56 x + 108$ can be factorized as $(x - 2) (x - 54)$ .

$⟹$ the roots are 2 and 54; both are positive.