Question

${\int }_0^{\frac{2}{3}}\frac{1}{4+9x^2}dx=$

• A. π/6
• B. π/12
• C. π/24
• D. π/4

Answer 1

The correct option is C

π/24

$I=\frac{1}{6}{\left[ta{n}^{-1}\left(\frac{3x}{2}\right)\right]}_0^{\frac{2}{3}}=\frac{\pi }{24}$