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Question

π20 3 sec x+5 cosec xsec x+cosec x dx=

A
π
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B
2 π
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C
3 π
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D
π2
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Solution

The correct option is B 2 π
π20 3 sec x+5 cosec xsec x+cosec x dx=π20 3 sec(π2x)+5 cosec(π2x)sec x+cosec xdx
=π20 3 cosec x+5 sec xsec x+cosec x dx
2I=π20 8 sec x+8 cosec xsec x+cosec x dx=8 π20 1 dx=8[x]π20=8 π2=4π

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