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Question

π20 cos x1+cos x+sin xdx=

A
π4+12log 2
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B
π4+log 2
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C
π412log 2
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D
π4log 2
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Solution

The correct option is C π412log 2
π20 cos x1+cos x+sin xdx
=π20cos2(x2)sin2(x2)2 cos2(x2)+2 sin(x2)cos(x2)dx
=12π201tan2(x2)1+tan(x2)dx=12π20[1tan(x2)]dx
π4+log 12=π412log 2

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